x^2+15x-11250=0

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Solution for x^2+15x-11250=0 equation:



x^2+15x-11250=0
a = 1; b = 15; c = -11250;
Δ = b2-4ac
Δ = 152-4·1·(-11250)
Δ = 45225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{45225}=\sqrt{225*201}=\sqrt{225}*\sqrt{201}=15\sqrt{201}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15\sqrt{201}}{2*1}=\frac{-15-15\sqrt{201}}{2} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15\sqrt{201}}{2*1}=\frac{-15+15\sqrt{201}}{2} $

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